3.12.85 \(\int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx\) [1185]

3.12.85.1 Optimal result
3.12.85.2 Mathematica [C] (verified)
3.12.85.3 Rubi [A] (warning: unable to verify)
3.12.85.4 Maple [F]
3.12.85.5 Fricas [A] (verification not implemented)
3.12.85.6 Sympy [F]
3.12.85.7 Maxima [F]
3.12.85.8 Giac [F(-2)]
3.12.85.9 Mupad [F(-1)]

3.12.85.1 Optimal result

Integrand size = 25, antiderivative size = 233 \[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=-\frac {i \sqrt {2} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{a}+\frac {i \sqrt {2} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{a}+\frac {i \log \left (1+\frac {\sqrt {a-i a x}}{\sqrt {a+i a x}}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2} a}-\frac {i \log \left (1+\frac {\sqrt {a-i a x}}{\sqrt {a+i a x}}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2} a} \]

output
1/2*I*ln(1-(a-I*a*x)^(1/4)*2^(1/2)/(a+I*a*x)^(1/4)+(a-I*a*x)^(1/2)/(a+I*a* 
x)^(1/2))/a*2^(1/2)-1/2*I*ln(1+(a-I*a*x)^(1/4)*2^(1/2)/(a+I*a*x)^(1/4)+(a- 
I*a*x)^(1/2)/(a+I*a*x)^(1/2))/a*2^(1/2)-I*arctan(1-(a-I*a*x)^(1/4)*2^(1/2) 
/(a+I*a*x)^(1/4))*2^(1/2)/a+I*arctan(1+(a-I*a*x)^(1/4)*2^(1/2)/(a+I*a*x)^( 
1/4))*2^(1/2)/a
 
3.12.85.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.89 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.30 \[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\frac {2 i \sqrt [4]{2} (1+i x)^{3/4} (a-i a x)^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {3}{4},\frac {7}{4},\frac {1}{2}-\frac {i x}{2}\right )}{3 a (a+i a x)^{3/4}} \]

input
Integrate[1/((a - I*a*x)^(1/4)*(a + I*a*x)^(3/4)),x]
 
output
(((2*I)/3)*2^(1/4)*(1 + I*x)^(3/4)*(a - I*a*x)^(3/4)*Hypergeometric2F1[3/4 
, 3/4, 7/4, 1/2 - (I/2)*x])/(a*(a + I*a*x)^(3/4))
 
3.12.85.3 Rubi [A] (warning: unable to verify)

Time = 0.31 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.89, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {73, 854, 826, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {4 i \int \frac {\sqrt {a-i a x}}{(i x a+a)^{3/4}}d\sqrt [4]{a-i a x}}{a}\)

\(\Big \downarrow \) 854

\(\displaystyle \frac {4 i \int \frac {\sqrt {a-i a x}}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{a}\)

\(\Big \downarrow \) 826

\(\displaystyle \frac {4 i \left (\frac {1}{2} \int \frac {\sqrt {a-i a x}+1}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}-\frac {1}{2} \int \frac {1-\sqrt {a-i a x}}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )}{a}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{\sqrt {a-i a x}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+\frac {1}{2} \int \frac {1}{\sqrt {a-i a x}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )-\frac {1}{2} \int \frac {1-\sqrt {a-i a x}}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )}{a}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (\frac {\int \frac {1}{-\sqrt {a-i a x}-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )}{\sqrt {2}}-\frac {\int \frac {1}{-\sqrt {a-i a x}-1}d\left (\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\sqrt {a-i a x}}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )}{a}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-\sqrt {a-i a x}}{-i x a+a+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )}{a}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-\frac {2 \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{\sqrt {a-i a x}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1\right )}{\sqrt {a-i a x}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}\right )\right )}{a}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{\sqrt {a-i a x}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1\right )}{\sqrt {a-i a x}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}\right )\right )}{a}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-\frac {2 \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{\sqrt {a-i a x}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}}{2 \sqrt {2}}-\frac {1}{2} \int \frac {\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}{\sqrt {a-i a x}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}+1}d\frac {\sqrt [4]{a-i a x}}{\sqrt [4]{i x a+a}}\right )+\frac {1}{2} \left (\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}\right )\right )}{a}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {4 i \left (\frac {1}{2} \left (\frac {\arctan \left (1+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (\sqrt {a-i a x}-\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\sqrt {a-i a x}+\frac {\sqrt {2} \sqrt [4]{a-i a x}}{\sqrt [4]{a+i a x}}+1\right )}{2 \sqrt {2}}\right )\right )}{a}\)

input
Int[1/((a - I*a*x)^(1/4)*(a + I*a*x)^(3/4)),x]
 
output
((4*I)*((-(ArcTan[1 - (Sqrt[2]*(a - I*a*x)^(1/4))/(a + I*a*x)^(1/4)]/Sqrt[ 
2]) + ArcTan[1 + (Sqrt[2]*(a - I*a*x)^(1/4))/(a + I*a*x)^(1/4)]/Sqrt[2])/2 
 + (Log[1 + Sqrt[a - I*a*x] - (Sqrt[2]*(a - I*a*x)^(1/4))/(a + I*a*x)^(1/4 
)]/(2*Sqrt[2]) - Log[1 + Sqrt[a - I*a*x] + (Sqrt[2]*(a - I*a*x)^(1/4))/(a 
+ I*a*x)^(1/4)]/(2*Sqrt[2]))/2))/a
 

3.12.85.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 826
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 
2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s)   Int[(r + s*x^2)/(a + b*x^ 
4), x], x] - Simp[1/(2*s)   Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ 
a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] 
 && AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 854
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + (m + 
 1)/n)   Subst[Int[x^m/(1 - b*x^n)^(p + (m + 1)/n + 1), x], x, x/(a + b*x^n 
)^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, - 
2^(-1)] && IntegersQ[m, p + (m + 1)/n]
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 
3.12.85.4 Maple [F]

\[\int \frac {1}{\left (-i a x +a \right )^{\frac {1}{4}} \left (i a x +a \right )^{\frac {3}{4}}}d x\]

input
int(1/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4),x)
 
output
int(1/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4),x)
 
3.12.85.5 Fricas [A] (verification not implemented)

Time = 0.24 (sec) , antiderivative size = 221, normalized size of antiderivative = 0.95 \[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\frac {1}{2} \, \sqrt {\frac {4 i}{a^{2}}} \log \left (\frac {{\left (a^{2} x + i \, a^{2}\right )} \sqrt {\frac {4 i}{a^{2}}} + 2 \, {\left (i \, a x + a\right )}^{\frac {1}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}{2 \, {\left (x + i\right )}}\right ) - \frac {1}{2} \, \sqrt {\frac {4 i}{a^{2}}} \log \left (-\frac {{\left (a^{2} x + i \, a^{2}\right )} \sqrt {\frac {4 i}{a^{2}}} - 2 \, {\left (i \, a x + a\right )}^{\frac {1}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}{2 \, {\left (x + i\right )}}\right ) + \frac {1}{2} \, \sqrt {-\frac {4 i}{a^{2}}} \log \left (\frac {{\left (a^{2} x + i \, a^{2}\right )} \sqrt {-\frac {4 i}{a^{2}}} + 2 \, {\left (i \, a x + a\right )}^{\frac {1}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}{2 \, {\left (x + i\right )}}\right ) - \frac {1}{2} \, \sqrt {-\frac {4 i}{a^{2}}} \log \left (-\frac {{\left (a^{2} x + i \, a^{2}\right )} \sqrt {-\frac {4 i}{a^{2}}} - 2 \, {\left (i \, a x + a\right )}^{\frac {1}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}{2 \, {\left (x + i\right )}}\right ) \]

input
integrate(1/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4),x, algorithm="fricas")
 
output
1/2*sqrt(4*I/a^2)*log(1/2*((a^2*x + I*a^2)*sqrt(4*I/a^2) + 2*(I*a*x + a)^( 
1/4)*(-I*a*x + a)^(3/4))/(x + I)) - 1/2*sqrt(4*I/a^2)*log(-1/2*((a^2*x + I 
*a^2)*sqrt(4*I/a^2) - 2*(I*a*x + a)^(1/4)*(-I*a*x + a)^(3/4))/(x + I)) + 1 
/2*sqrt(-4*I/a^2)*log(1/2*((a^2*x + I*a^2)*sqrt(-4*I/a^2) + 2*(I*a*x + a)^ 
(1/4)*(-I*a*x + a)^(3/4))/(x + I)) - 1/2*sqrt(-4*I/a^2)*log(-1/2*((a^2*x + 
 I*a^2)*sqrt(-4*I/a^2) - 2*(I*a*x + a)^(1/4)*(-I*a*x + a)^(3/4))/(x + I))
 
3.12.85.6 Sympy [F]

\[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\int \frac {1}{\left (i a \left (x - i\right )\right )^{\frac {3}{4}} \sqrt [4]{- i a \left (x + i\right )}}\, dx \]

input
integrate(1/(a-I*a*x)**(1/4)/(a+I*a*x)**(3/4),x)
 
output
Integral(1/((I*a*(x - I))**(3/4)*(-I*a*(x + I))**(1/4)), x)
 
3.12.85.7 Maxima [F]

\[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\int { \frac {1}{{\left (i \, a x + a\right )}^{\frac {3}{4}} {\left (-i \, a x + a\right )}^{\frac {1}{4}}} \,d x } \]

input
integrate(1/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4),x, algorithm="maxima")
 
output
integrate(1/((I*a*x + a)^(3/4)*(-I*a*x + a)^(1/4)), x)
 
3.12.85.8 Giac [F(-2)]

Exception generated. \[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\text {Exception raised: TypeError} \]

input
integrate(1/(a-I*a*x)^(1/4)/(a+I*a*x)^(3/4),x, algorithm="giac")
 
output
Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:The choice was done assuming 0=[0,0 
]ext_reduce Error: Bad Argument TypeDone
 
3.12.85.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{3/4}} \, dx=\int \frac {1}{{\left (a-a\,x\,1{}\mathrm {i}\right )}^{1/4}\,{\left (a+a\,x\,1{}\mathrm {i}\right )}^{3/4}} \,d x \]

input
int(1/((a - a*x*1i)^(1/4)*(a + a*x*1i)^(3/4)),x)
 
output
int(1/((a - a*x*1i)^(1/4)*(a + a*x*1i)^(3/4)), x)